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Mathematics module 3

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Score for this quiz: 42 out of 50Submitted May 23 at 12:43am This attempt took 90 minutes. Q 1. 5 / 5 pts Find the answer to each of the following by first reducing thefractions as much as possi ... ble: a) P (412,3)= b) C(587,585)= Your Answer: a) Permutation P(n,r)=n!/(n-r)! P(412,3)= 412/(412-3)!=412!/409= 412(411)(410)=69,426,120 b) Combination C(n,r)=n!/r!(n-r)! C(587,585)= 587/585!(587-585)= 587!/585!582!= 587(586)/2(1)=171,991Suppose A and B are two events with probabilities: P(A)=.30,P(B)=.30,P(A∩B)=.10. Find the following: a) P(A∪B). b) P(Ac ). c) P(Bc ). Your Answer: a) P(A ∪ B)= P(A)+P(B)-P(A ∩ B) P(A ∪ B)= .70+.70-.10 = 1.5 b) P(Ac) P(A)= 1-P(Ac) = 1-.30 = .70 c) P(Bc) P(B)= 1-P(Bc) = 1-.30 = .70 a. For P(A∪B). Use P(A∪B)=P(A)+P(B)-P(A∩B).P(A∪B)=.30+.30- .10=.5. This study source was downloaded by 100000868573857 from CourseHero.com on 06-21-2023 03:18:58 GMT -05:00 https://www.coursehero.com/file/66267281/Exam-3-Stat-Module-3pdf/ b. For P(Ac ). Use P(A)=1-P(Ac ) which may be rearranged to(Ac )=1-P(A) . P(Ac )=1-.30=.70. c. For P(Bc ). Use P(B)=1-P(Bc ) which may be rearranged to(Bc )=1-P(B) . P(Bc )=1-.30=.70. ................................CONTINUED........................................... [Show More]

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