Mathematics  >  A/As Level Mark Scheme  >  > GCE Further Mathematics B (MEI) Y420/01: Core Pure Advanced GCE Mark Scheme for Autumn 2021 (All)

> GCE Further Mathematics B (MEI) Y420/01: Core Pure Advanced GCE Mark Scheme for Autumn 2021

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Mark Scheme October 2021 7 Question Answer Marks AOs Guidance 2 DR 2 d 1 6 2 d 1 4 y x x =   − 14 34 d 1 when , 6 2 8 3 y d x x = =   = B1 M1 A1 A1 [4] 1.1 1.1 ... 1.1 1.1 ? √1−4?2 Chain rule (x 2) Fully correct ?? ?? Alternative solution DR sin ? 6 = 2? ?? ?? = 1 12 cos ? 6 ?? ?? = 12 cos ? 6 and ? = 1 4 , ? = ? → ?? ?? = 8√3 M1 M1 A1 A1 For ?? ?? = ? cos ? 6 Using chain rule (× 1 6 ) Or 2 d 1 6 2 d 1 4 y x x =   −Y420/01 Mark Scheme October 2021 8 Question Answer Marks AOs Guidance 3 (a) DR z1 = 8 1 3 arg( ) 4 z  = B1 E1 [2] 1.1 1.1 Must see some reasoning for arg(z) 3 (b) DR 1 2 8 2 2 z z = = arg(zz12 )= − = 3 7 4 6 12    so zz12 = + 2 cos isin ( 7 7 12 12   ) B1 M1 A1 B1 [4] 1.1 1.1 1.1 1.1 arg arg( ) arg( ) ( zz12 )= − z z 1 2 used 4 DR 1 2 1 1 1 mean d 1 ( 1) 1 4 x x − = − − +  1 2 1 14 1 1 d 8 x x − = +  1 1 1 2arctan 2 8 x − =     1 arctan 2 0.554 2 =  B1 M1 A1 A1 [4] 1.1 1.1 1.1 1.1 or 2 2 2 1 1 1 2 d 2 2 1 u x u − u =  +  2 2 1 arctan 4 u − =     [Show More]

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