CHEM 120 Final Exam
1. Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Pts. : 5)
2. Question: (TCO 1)
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CHEM 120 Final Exam
1. Question: (TCO 8) 35.0 mL of 0.25 M NaOH is neutralized by 23.6 mL of an HCl solution. The molarity of the HCl solution is (show your work): (Pts. : 5)
2. Question: (TCO 1) How many mL are in 3.5 pints? Show your work. (Pts. : 5)
3. Question: (TCO 3) What is the name of the following compound: Zn3P2? (Pts. : 5)
4. Question: (TCO 3) What is the name of the following compound: AgNO3? (Pts. : 5)
5. Question: (TCO 6) Calculate the pressure, in atmospheres, of 2.78 mol CO(g) in a 4.25 L tank at 51 degrees C. (Pts. : 5)
6. Question: (TCO 6) A gas at a temperature of 95 degrees C occupies a volume of 165 mL. Assuming constant pressure, determine the volume at 25 degrees C. Show your work. (Pts. : 5)
Using Charles’ Law, (V1/T1) = (V2/T2).
First, convert temperature to KELVIN (T1 = t1 +273)
Thus, T1 = 95 + 273 = 368.
We have V1 (165 mL) & T2 = (25 + 273) = 298.
V2 = (V1*T2)/T1 = (165 mL*298)/368 = 133.6 mL.
7. (TCO 6) A sample of helium gas occupies 1021 mL at 719 mmHg. For a gas sample at constant temperature, determine the volume of helium at 745 mmHg. Show your work. (Pts. : 5)
1021mL * 719 mm/745 mmHg = 985.36mL =985mL
Using Boyle’s law, P1V1 = P2V2. We have V1 (1021 mL), P1 (719 mmHg) and P2 (745 mmHg).
8. (TCO 12) If one strand of a DNA double helix has the sequence T T A G C G A C G C, what is the sequence of the other DNA strand? (Pts. : 10)
A A T C G C T G C G
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