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SYSC 3310: Introduction to Real Time Systems Lecture 14: Midterm correction

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SYSC 3310: Introduction to Real Time Systems Lecture 14: Midterm correction Dr. Paulo Garcia Assistant Professor Department of Systems and Computer EngineeringMidterm results • 75% achieved a ... passing mark • Class average: 64% • Passing mark average: 74%Midterm • The main purpose of having a midterm is to give you feedback • Specifically, identifying what you’re doing wrong or do not know • I care about what you will know at the end of the course • In other words, no one fails because of a midterm aloneCourse evaluation • You only get lab marks if you have more than 50% in either midterm or final • Otherwise, mark is 50% midterm + 50% final • If your midterm mark is better than your final mark: • 20% labs + 35% midterm + 45% final • If your final mark is better than midterm mark: • 20% labs + 80% finalQuestion 1 (average = 7%) • 1: Given three registers REG_A, REG_B and REG_C, at addresses 0x7000466, 0x7000468 and 0x700046A, respectively; which type cast should you use in the following code that writes 0 to REG_B? Why (justify)? REG_B = ( )0;Question 1 • 1: Given three registers REG_A, REG_B and REG_C, at addresses 0x7000466, 0x7000468 and 0x700046A, respectively; which type cast should you use in the following code that writes 0 to REG_B? Why (justify)? REG_B = ( uint16_t )0; registers are 2 bytes in size 0x7000468 - 0x7000466 = 2 0x700046A - 0x7000468 = 2 REG_A (bits 15 to 8) REG_A (bits 7 to 0) 0x700046B 0x700046A 0x7000469 0x7000468 0x7000467 0x7000466Question 1: misconceptions • 0x7000466 = 28bits, hence registers are 28 bits X • Size of the address has nothing to do with size of what we’re addressing • You could use an 8 bits address (e.g., 0x80) to address 8 bit registers. 16 bit registers, 32 bit registers….. etc • Registers are two bits apart X • 1 byte = 8 bits • Memory is always byte-addressableQuestion 2 • 2: Assume the pins in Port 1 are connected to external devices (active low buttons for input and active high motors for output) as in the diagram below. 0 1 2 3 4 5 6 7 Port 1 Button MotorQuestion 2a (average = 53%) • 2a: What is wrong with the following code to start the motor connected to pin 3? Justify and write the correct code. • P1OUT = (uint8_t)0x8;Question 2a • 2a: What is wrong with the following code to start the motor connected to pin 3? Justify and write the correct code. • P1OUT = (uint8_t)0x8; • P1OUT = 0b00001000 Clearing every [Show More]

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