Cambridge International AS & A Level MATHEMATICS 9709/21 Paper 2 Pure Mathematics 2 2022 + MARK SCHEME

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1 The variables x and y satisfy the equation y = 42x−a, where a is an integer. As shown in the diagram, the graph of ln y against x is a straight line passing through the point 0, −20.8
, where ... the second coordinate is given correct to 3 significant figures. (a) Show that the gradient of the straight line is ln 16. [2] ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ (b) Determine the value of a. [2] ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ © UCLES 2022 9709/21/M/J/223 2 (a) Express the equation 7 tan 1 + 4 cot 1 − 13 sec 1 = 0 in terms of sin 1 only. [3] ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ (b) Hence solve the equation 7 tan 1 + 4 cot 1 − 13 sec 1 = 0 for 0Å < [Show More]

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