Mathematics > GCSE MARK SCHEME > Mark Scheme (Results) January 2021 Pearson Edexcel International GCSE Mathematics A (4MA1) Paper 1HR (All)

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Mark Scheme (Results) January 2021 Pearson Edexcel International GCSE Mathematics A (4MA1) Paper 1HR/ Graded A+

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International GCSE Maths Apart from questions 1, 8, 10, 11d, 12c, 14, 15ab, 17 (where the mark scheme states otherwise) the correct answer, unless clearly obtained by an incorrect method, should be ... taken to imply a correct method Question Working Answer Mark Notes 1 e.g. 16 5 and 11 6 or 96 30 and 55 30 3 M1 for two correct improper fractions e.g. 8 3 16 11 5 6  or 176 30 or 5280 900 oe M1 correct cancelling or multiplication of numerators and denominators without cancelling e.g. 16 11 176 88 13 5 5 6 30 15 15  = = = or 16 11 176 26 13 5 5 5 6 30 30 15  = = = or 8 3 16 11 88 13 5 5 6 15 15  = = or 96 55 5280 88 13 5 30 30 900 15 15  = = = NB: a student can show initially that and they need to show that LHS = shown A1 Dep on M2 for conclusion to 513 15 from correct working – either sight of the result of the multiplication e.g. 176 30 must be seen and equated to 88 15 or 26 5 30 or correct cancelling prior to the multiplication to 88 15 NB: use of decimals scores no marks Total 3 marks 13 88 5 15 15 = 88 152 a = 7 4 B1 their 8.5 2 b a + = oe or b = 10 M1 ft their value of a or for setting up an equation for b or b = 10 their their their 9 4 a a b c + + + = oe or (c =) 9 × 4 – (2 × their a + their b) oe M1 for a calculation involving c using their values or for a calculation leading to c using their values 7, 10, 12 A1 Total 4 marks 3 a Correct number line 2 B2 B1 for a fully correct number line e.g. shaded circle at −2, unshaded circle at 1 and a line drawn between them for a shaded circle at −2 or an unshaded circle at 1 or circles at −2 and 1 with line in between but shading incorrect b −3, −2, −1, 0, 1, 2 2 B2 B1 fully correct values with no extras for 5 correct values and none incorrect or all 6 correct values with no more than one additional incorrect value Total 4 marks4 3.4 or 17 5 or 2 3 5 or 24 3 60 or 204 oe 3 B1 433.5 ÷ 3.4 or 433.5 ÷17 5 or 433.5 ÷3 2 5 or 433.5 60 '204'  oe M1 for use of speed = distance ÷ time Allow 433.5 ÷ 3.24 (= 133.796…) for this mark only 127.5 A1 oe allow 128 Total 3 marks 5 a (x =) 270 ÷ (12 × 5) (= 4.5) oe 3 M1 π × ‘4.5’2 × 2 × ‘4.5’ (= 182.25π oe) M1 ft dep on M1 573 A1 accept 572 − 573 b 1 000 000 1 B1 or (1 × ) 106 or (one or 1) million oe Total 4 marks 6 a e.g. A + 5z = c y oe or Ay = c – 5yz oe 2 M1 for a correct first step e.g. add 5z to both sides or multiply all terms by y c = y(A + 5z) A1 oe b 1 1 B1 c (x ± 3)(x ± 8) 2 M1 or for (x ± a)(x ± b) where ab = 24 or a + b = − 11 (x − 3)(x − 8) A1 Total 5 marks7 0.024 × 50 000 (= 1200) oe or 1.024 × 50 000 (= 51 200) oe or 1.0242 × 50 000 (= 52 428.8) oe or 0.024 × 50 000 × 3 (= 3600) oe 0.024 × 50 000 × 3 + 50 000 (= 53 600) oe 3 M1 M2 for 50 000 × 1.0243 0.024 × (50 000 + ‘1200’) (= 1228.8) oe and 0.024 × (50 000 + ‘1200’ + ‘1228.8’) (= 1258.2912) or ‘1200’ + ‘1228.8’ + ‘1258.2912’ (= 3687.(0912)) or 1.024 × ‘52 428.8’ M1 for completing method to find total amount in the account 53 687 A1 accept 53 687 – 53 688 accept (1 + 0.024) or 1 2.4 100     +   as equivalent to 1.024 throughout Total [Show More]

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