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Mark Scheme (Results) January 2022 Pearson Edexcel International GCSE In Mathematics B (4MB1) Paper 02R

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Ques Working Answer Mark Notes 1 (a) 4 1 B1 (b) 1.5 1 B1 oe (c) g(4) = 3 2 M1 27 A1 Total 4 marks 2 (a) −4 − 6 < 3x + 2x or 3x + 2x  21 – 6 oe 3 M1 oe one of −2 < x or x  3 oe M1 ... oe −2 < x  3 A1 oe (b) 4x² − 8x −21(= 0) (2x – 7)(2x + 3)(= 0) 3 M1 oe rearranged and attempt to solve quadratic (critical values) 3.5 and −1.5 M1 NB working not required −1.5 < x < 3.5 A1 (c) 2 B2 completely correct (ft their values from (a) and (b) so long as possible on the number line) (B1 for a line between −1.5 and 3 with incorrect shading of dots or one end shaded correctly) Total 8 marks https://britishstudentroom-b430a.web.app/3 (a) 3 B1 for LH branches 7 3 (0.46...), oe(0.2) 15 15 B2 for all remaining branches (B1 for 5, 6, 7, 8 branches) 8 9 3 oe (0.4), (0.45), (0.15) 20 20 20 repeated 3 times (b) 3 M1ft their tree diagram for any two correct products for method used 5 8 7 9 3 3 1 ( ) 15 20 15 20 15 20 −  +  +  oe or 5 9 3 7 8 3 3 8 9 ( ) ( ) ( ) 15 20 20 15 20 20 15 20 20  + +  + +  + oe M1ft their tree diagram for a fully correct method 47 75 A1 oe (0.626...) (c) 3 3 19 15 20 1000   = x oe eg 0.2 × 0.15 × x = 0.019 3 M1ft their tree diagram 19 300 19 " "( ) 1000 9 30 x =  = oe x = 0.019 ÷ 0.03 (0.633...) M1ft their tree diagram 30 A1 Total 9 marks https://britishstudentroom-b430a.web.app/4 (a) 8 6 11 3 14 10 10 5 −   −         − − oe 3 M1 3 9 24 15   −     − A1 1 3 8 5   −     − A1 (award 2 marks for 3 out of 4 terms of this matrix correct) (b) 5 27 63 4   −     − 2 B2 correct (B1 for 3 correct values in a matrix of correct order) (c) 1 5 3 25 10 11   − −     − oe 2 B2 correct (B1 for a correct method to find the determinant and 2 other values correct or 4 correct values in matrix and one mistake in determinant) (d) 22 45 42 11 23 7   −     − −     2 B2 correct (B1 for 3, 4 or 5 correct values in a matrix of correct order) [Show More]

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