Electrical Engineering > Solutions Guide > University of Michigan - EECS 484HW4 Solution (All)

University of Michigan - EECS 484HW4 Solution

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Question 1 (20 points) 1.1) (6 points) Block Nested Loops Join (A) Reads = |R| + |S| * ceil(|R|/(B-2)) = 5,000 + 15,000 * ceil(5,000/(800-2)) = 110,000 (B) Writes = 0 (no writes are required fo ... r nested loops joins) 1.2) (7 points) Grace Hash Join (A) Reads in Partition phase = |R| + |S| = 20,000 Reads in Probe phase = |R| + |S| = 20,000 Total reads = 2 * (|R| + |S|) = 40,000 (B) Total writes = |R| + |S| = 20,000 1.3) (7 points) BNJ = 110,000 * 1 [reads; no writes] = 110,000 GHJ = 40,000 * 1 [reads] + 20,000 * X [writes] From BNJ = GHJ → 110,000 = 40,000 + 20,000 * 3.5, we get X = 3.5 So we should choose BNJ if X > 3.5, but GHJ if X < 3.5 Question 2 (20 points) 2.1) (4 points) B - 1 buckets 2.2) (4 points) Recursively apply hash-based projection technique to further split the buckets with different hash functions until no more partition overflow. 2.3) (4 points) (B - 1)^2 buckets 2.4) (4 points) Accelerate the record matching in memory or reduce CPU cost of record matching. 2.5) (4 points) No. In the probing phase, using the same hash function will assign each data record into the same bucket. No speeding up for join in the probing phase is obtained by using the same hash function. [Show More]

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