Question 1
The straight line distance between two points is known as its
The distance between two points is the length of the line segment that connects them.
The correct option is: [4] length
Question 2
Find the pe
...
Question 1
The straight line distance between two points is known as its
The distance between two points is the length of the line segment that connects them.
The correct option is: [4] length
Question 2
Find the perimeter of the diagram below
Perimeter = (10 + 15 + 4 + 4 + 6 + 11) m = 50 m
The correct option is: [3] 50 m
Question 3
Find the perimeter of the shaded region in the figure below, if ABCD is a square of side 14 cm
and APB and CPD are semicircles, rounded off to the nearest integer.
Side of a square (AB=BC=AD=CD) = 14 cm
Diameter of circle= side of square= 14 cm
Radius of circle = 7cm
Perimeter of the shaded region = perimeter of semicircle DPC + perimeter of semicircle APB + AD + BC
= πr + πr + 14 + 14 = 2 πr + 28 = 2×3.14×7 + 28 = 72 cm
Hence, the Perimeter of the shaded region = 72 cm.
The correct option is: [1] 72 cm
ASSIGNMENT 03 2022
Study material: Chapters 4 and 5 in the Study Guide
3
Question 4
If 1 m = 100 cm, then how many cm
2
are there in a m
2
?
If 1 m = 100 cm, then (1 m)
2
= (100 cm)
2 ⟹1 m
2
= 10 000 cm2
The correct option is: [4] 10 000 cm
2
Question 5
Farmer Bob needs to build a fence for his chickens. The area he wants to build a fence around is
40 m long and the width is half of the length. How many square meters of fence does he need to
buy?
Length (L) = 40 m
Width (W) = Half Length = 40÷2 =20 m
The area, A = LW = 40 m × 20 m = 800 m
2
The correct option is: [1] 800 m
2
Question 6
Find the area of triangle ABC:
Area of triangle ABC = 0,5×base×h = 0,5×1×1 = 0,5 =
1
cm2
2
The correct option is: [4] 1 cm
2
2
Question 7
From a rectangular metal sheet of sides 25 cm and 20 cm, a circular sheet as large as possible is
cut-off. What is the area of the remaining sheet, rounded off to the nearest integer?
Area of the remaining sheet = area of the rectangle - area of the circle
The diameter of the circle = breadth of the rectangle = 20 cm.
Hence the radius of the circle = 10 cm.
Area of the remaining sheet = l×b – πr
2
= 25×20 – 3.14× 102
= 500 – 314 =186 cm2
The correct option is: [1] 186 cm
2
CONTINUES...
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